How to estimate 95 % confidence interval of population average from sample average and sample standard deviation?

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If you had known average and standard deviation of sample which size is N, you could estimate the range of population average with 95 % probability. In standard normal distribution, sum of area under curve greater than 1.96 and less than – 1.96 is 0.05. There is population average between exception multiplying 1.96 by standard error from average and sum of the multiplied and average, called as 95 % confidence interval (95 % CI).

\displaystyle 95 \% C.I.= \mu \pm 1.96 SE = \mu \pm 1.96 \frac{SD}{\sqrt N}

\mu; Average, SE; standard error, SD; standard deviation

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